bash - Remove part of the path in shell -

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echo "/dir1/dir2/filename.txt" | sed ????

what should sed expression output 

   /dir1/filename.txt

if there other simpler way achieve this, welcome.

you can cut:

$ echo "/dir1/dir2/filename.txt" | cut -d/ -f1,2,4 /dir1/filename.txt

with sed little mess:

$ echo "/dir1/dir2/filename.txt" | sed 's/^\(\/.*\)\(\/.*\)\(\/.*\)/\1\3/' /dir1/filename.txt

the idea portions of /text \(\/.*\) , print ones want, 1 , 3, \1\3.


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