c - 3d array as function argument -

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i have function takes 2d-array argument. have 3d-array e.g. temp[5][100][100]. want pass 2d portion of array function. how can this?

int inteference_sets(int array[][],int array_size,int max_channel){      //function codes } int main(){     int k;      int temp[5][100][100];     for(k=1;k<=4;k++){        interference_sets(temp[k], , ) //this how program intends work     }  }

is possible? if yes, how?

#define dim1 100 #define dim2 100  int inteference_sets(int (*array)[dim2], int array_size, int max_channel) {      int row, col;       for( row = 0; row < array_size; row++ )      {          for( col = 0; col < dim2; col++ )          {              int value = array[row][col];              //function codes          }      } }   int main() {     int k;      int temp[5][dim1][dim2];      for(k=1;k<=4;k++)     {        interference_sets(temp[k], dim1, ) //this how program intends work     }  }

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