html5 - How can I change a CSS gradient via JavaScript? -

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i have div following gradient applied it:

/* mozilla firefox */  background-image: -moz-linear-gradient(top, #2e2e28 0%, #4d4c48 100%); /* opera */  background-image: -o-linear-gradient(top, #2e2e28 0%, #4d4c48 100%); /* webkit (safari/chrome 10) */  background-image: -webkit-gradient(linear, left top, left bottom, color-stop(0, #2e2e28), color-stop(1, #4d4c48)); /* webkit (chrome 11+) */  background-image: -webkit-linear-gradient(top, #2e2e28 0%, #4d4c48 100%); /* ie10+ */ background: -ms-linear-gradient(top,  #2e2e28 0%,#4d4c48 100%); /* w3c */ background: linear-gradient(top,  #2e2e28 0%,#4d4c48 100%);

how change "#2e2e28" number, still avoid cross-browser nightmare?

with jquery it'll :

$('.gradient').css({'background-image': 'linear-gradient(to top,  #2e2e28 0%, #4d4c48 100%)'});

for safari :

$('.gradient').css({'background-image': '-webkit-linear-gradient(top,  #2e2e28 0%, #4d4c48 100%)'});

see here live example.

seems work cross-browser.

edit :

i did small plugin can different colors :

;(function($) {     var issafari = /safari/.test(navigator.useragent) && /apple computer/.test(navigator.vendor);      var methods = {         init: function (settings) {              settings = $.extend( {               'colors'         : ['red', 'blue'],               'direction'      : 'top'             }, settings);              return this.each(function(){                 if($.isarray(settings.colors) && settings.colors.length >= 2) {                     $(this).css({                          'background':                         methods.gradienttostring(settings.colors, settings.direction)                     });                 } else {                     $.error('please pass array');                 }              });          },         gradienttostring: function (colors, direction) {              var nbcolors = colors.length;              //if no percent, need calculate them             if(colors[0].percent === undefined) {                  //passed colors array make object                 if(colors[0].color === undefined) {                     var tmp = [];                     for(i=0; < nbcolors; i++)                         tmp.push({'color':colors[i]});                      colors = tmp;                 }                  var p = 0,                     percent = 100 / (nbcolors - 1);                  //calculate percent                 for(i=0; i< nbcolors; i++) {                     p = === 0 ? p : (i == nbcolors-1 ? 100 : p + percent);                     colors[i].percent = p;                 }             }              var = issafari ? '' : 'to';              //build string             var gradientstring = issafari ? '-webkit-linear-gradient(' : 'linear-gradient(';             gradientstring += +' '+ direction;              for(i=0; < nbcolors; i++)                gradientstring += ', '+ colors[i].color + ' ' + colors[i].percent + '%';              gradientstring += ')';             return gradientstring;          }      };      $.fn.gradientgenerator = function () {         return methods.init.apply( this, arguments );     }; })(jquery);

use example :

$('.gradient').gradientgenerator({     colors : ['#2e2e28', '#4d4c48'] });  $('.change-color').on('click', function(e) {      e.preventdefault();     $('.gradient').gradientgenerator({         colors : [{color:'#4d4c48',percent:0}, {color:'#282827', percent:30}, {color:'#2e2e28', percent: 100}],         direction : 'left'     });  });

see working here.


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