Forcing whitespace in Bash arrays being passed into grep -

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i have pretty simple bash script should grep file multiple phrases want flag.

it works until point, falling on when want grep ' print ' or ' puts ' (note whitespace before , after word).

the grep ignoring whitespace in input.

here code (stuff isn't relevant has been cut out)

#!/bin/sh  bad_phrases=('console.log(' 'binding.pry' ':focus,' 'alert(' ' print ' ' puts ') bad_phrase_found=false  file='my_test_file.txt'  bad_phrase in ${bad_phrases[*]} ;   if grep -q "$bad_phrase" $file ;       bad_phrase_found=true       echo "a '$(tput bold)$(tput setaf 1)$bad_phrase$(tput sgr0)' found in $(tput bold)$(tput setaf 5)$file$(tput sgr0)"   fi done  if $bad_phrase_found ;   exit 1 fi  exit 0

i have looked @ setting ifs '~' , splitting array way, killed grep command completely.

the example output of script is;

'print' found in my_test_file.txt

any appreciated.

you need use "${bad_phrases[@]}". don't forget double quotes. should make habit quote variables in order suppress word splitting.

for bad_phrase in "${bad_phrases[@]}" ;   if grep -q "$bad_phrase" "$file" ;       bad_phrase_found=true       echo "a '$(tput bold)$(tput setaf 1)$bad_phrase$(tput sgr0)' found in $(tput bold)$(tput setaf 5)$file$(tput sgr0)"   fi done

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