date - Can anyone explain this curious batch behavior using "%~t1" and give a solution -

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can explain following me:

the code:

@echo off setlocal disabledelayedexpansion  set pf=c: set url=http://www.rarlab.com/rar set fn=config.sys  call :sub1 "%url%" "%fn%" goto :eof  :sub1 echo:path=[ %pf%\%~2 ] if exist %pf%\%~2 (call :readdate "%pf%\%~2") & set "_datum1=%_result%" echo:date1=[ %_datum1% ] if exist %pf%\%~2 (call :readdate "%pf%\%~2") & set "_datum2=%_result%" echo:date2=[ %_datum2% ] goto :eof  :readdate setlocal %%a in (%~1) set "_tvar=%%~ta" echo:date=[ %_tvar% ] endlocal & set "_result=%_tvar%" exit /b 0   :end

the output:

path=[ c:\config.sys ] date=[ 10.06.2009 23:42 ] date1=[  ] date=[ 10.06.2009 23:42 ] date2=[ 10.06.2009 23:42 ]

so if @ line 3 of output there no date/time - why ????? if it's not big bug of cmd.exe can please me solving problem. need both date/time data comparison.

addendum:

is somehow possible read date/time in first "sub" without using second "readdate" ??

i tried following:

if exist %pf%\%~2 set "_datum1=%pf%\%~t2"

but not work because "~t2" seems work variable holds full path , filename together.

@echo off setlocal disabledelayedexpansion  set pf=c: set url=http://www.rarlab.com/rar set fn=config.sys  call :sub1 "%url%" "%fn%" goto :eof  :sub1 echo:path=[ %pf%\%~2 ] if exist %pf%\%~2 (call :readdate "%pf%\%~2") set "_datum1=%_result%" echo:date1=[ %_datum1% ] if exist %pf%\%~2 (call :readdate "%pf%\%~2") set "_datum2=%_result%" echo:date2=[ %_datum2% ] goto :eof  :readdate setlocal %%a in (%~1) set "_tvar=%%~ta" echo:date=[ %_tvar% ] endlocal & set "_result=%_tvar%" exit /b 0   :end

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