c++ - passing pointer type to template argument -

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i wrote following code:

template <typename t> void  myname(t* x) {     cout<<"x "<<x; }

and invoked:

char *p="stackoverflow"; myname(p);

it prints stackoverflow.

but if change template argument (t* x) (t x) same result.

so difference between 2 template parameters?

void  myname (t x)

and 

void myname (t* x)

first case - t deduced char, t* char*. second case - t deduced char*. differences here in call such function

for first case should be

myname<char>(p);

and second

myname<char*>(p);

also, differences when use type t in function.


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