c++ - passing pointer type to template argument -

i wrote following code:

template <typename t> void  myname(t* x) {     cout<<"x "<<x; } 

and invoked:

char *p="stackoverflow"; myname(p); 

it prints stackoverflow.

but if change template argument (t* x) (t x) same result.

so difference between 2 template parameters?

void  myname (t x)   

and

void myname (t* x) 

first case - t deduced char, t* char*. second case - t deduced char*. differences here in call such function

for first case should be

myname<char>(p); 

and second

myname<char*>(p); 

also, differences when use type t in function.