php json data return jquery -

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looking best solution:

$.getjson("insertdata.php", {fullname:val1, course_id:course_id, occupation:val2}, function(data) {         $.each(data, function(i, user) {             //alert(user.arya.status);             if(user.arya.status == 'true'){                 currentposition = 2;                 checkdata();                 nextslide();             }else{                  nextslide();             }         });      })

here php code:

    mysql_select_db("db", $con);      $query="select * table fullname='".$fullname."' , course_id='".$cid."'";     $result = mysql_query($query);     $totalrecords = mysql_num_rows($result);     if($totalrecords) {         while ($row = mysql_fetch_array($result)) {                 $returndata[]=array(    //for json data array             'username' => $row['fullname'],             'arya' => array(                 'status' => $row['status']                 )             );         }      }      if(!$totalrecords) {         $insertquery="insert table (fullname,course_id,occupation) values ('".addslashes($fullname)."','".addslashes($cid)."','".addslashes($d3)."')";         $result1 = mysql_query($insertquery);      }else{         if($stat == "true"){$value = 1;}         }  mysql_close($con);  echo json_encode($returndata);

so in first case when hit php through jquery saves data in database give me error or length. because $returndata empty. there way if $totalrecords false, how send json_encode there no data or value through json_encode jquery function.

thanks in advance.

$returndata = array(); //add  $totalrecords = mysql_num_rows($result); if($totalrecords) { while ($row = mysql_fetch_array($result)) {         $returndata[]=array(    //for json data array     'username' => $row['fullname'],     'arya' => array(         'status' => $row['status']         )     ); }  } else { $returndata[] = 'no record'; //add }

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