x86 64 - In GDB how do I print 0xc(%rsp)? -

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i'm trying debug code project , i've come against line cmpl $0x7,0xc(%rsp). 0xc(%rsp), , how print it?

what 0xc(%rsp)

the memory location 12 bytes above current stack pointer. value @ location being compared 7.

and how print it?

(gdb) print $rsp+0xc

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