regex - How to display the exact search keyword in perl -

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i using regex searching directory list of keywords. here current code: 

   if (/$search/i)     {          printf $out "%s\t%s\n",$file::find::name,$1;           }

in above code $1 giving keyword phrase. want entire keyword.

example: searching "sweep"

current output: c:\ac\acfrd\file.sql sweep. file contains word "sweep_id", , want output "sweep_id", not "sweep".

try regex: 

/\b(\w*$search\w*)\b/i

it captures search term , optional adjacent word-symbols (\w - letters, digits, etc.) $1. captured character sequence surrounded word-boundaries (\b - punctuation, whitespace, string beginning or ending).

the regex above allows additional word-symbols both before , after search term. if want allow additional symbols after search term (as in example), remove first \w*: 

/\b($search\w*)\b/i

if not want rely on perl's definition of "word symbols", replace \w own character class, e.g. (only allow letters , underscores): 

/\b([_a-z]*$search[_a-z]*)\b/i

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